Mastering the Move Zeroes Problem in Python – LeetCode 75 Explained

Move Zeroes is a classic array manipulation problem from the LeetCode 75 challenge list. It evaluates your grasp of in-place updates, the two-pointer approach, and efficient iteration techniques. While the objective—moving all zeroes to the end of the list—might appear straightforward, performing the operation in-place, without disrupting the order of non-zero elements, adds a layer of complexity.

In this blog post, we’ll break down the Move Zeroes problem in Python step-by-step. We’ll explain how the code works, outline the logic behind each operation, and help you strengthen your understanding of a frequently asked coding interview question.

Problem Statement

Given an integer array nums, move all 0‘s to the end of the array while maintaining the relative order of the non-zero elements.

Important Conditions:

  • Modify the input array in-place.
  • Don’t return a new array.
  • Aim for minimal operations.

What does “Move Zeroes” mean?

  • All non-zero elements must retain their original order.
  • All zeroes must be moved to the end.
  • The modification must be done without using extra space for another array.

Examples

Input:  [0, 1, 0, 3, 12]
Output: [1, 3, 12, 0, 0]

Input:  [1, 0, 2, 0, 3]
Output: [1, 2, 3, 0, 0]

Python Solution – Step-by-Step Explanation

Let’s look at the optimal solution using the two-pointer technique and explain it in detail:

class Solution:
    def moveZeroes(self, nums: List[int]) -> None:
        """
        Do not return anything, modify nums in-place instead.
        """
        non_zero_index = 0

        for i in range(len(nums)):
            if nums[i] != 0:
                nums[non_zero_index], nums[i] = nums[i], nums[non_zero_index]
                non_zero_index += 1

        for i in range(non_zero_index, len(nums)):
            nums[i] = 0

Step 1: Initialize Pointer

non_zero_index = 0
  • This pointer tracks the position where the next non-zero value should be placed.
  • It also represents the boundary between processed non-zero values and the rest of the array.

Step 2: Traverse the Array and Swap

for i in range(len(nums)):
    if nums[i] != 0:
        nums[non_zero_index], nums[i] = nums[i], nums[non_zero_index]
        non_zero_index += 1
  • Loop through each element.
  • If you find a non-zero, swap it with the element at non_zero_index.
  • Move the pointer forward to prepare for the next non-zero placement.
  • This effectively pushes all non-zero elements to the beginning, preserving their order.

Step 3: Fill the Remaining Positions with Zeroes

for i in range(non_zero_index, len(nums)):
    nums[i] = 0
  • Once all non-zero elements are at the beginning, fill the rest of the array with 0.
  • This finalizes the in-place transformation.

Why This Solution Works

This solution is:

  • Efficient: Only makes one full pass through the array.
  • In-place: Doesn’t use any extra memory.
  • Stable: Maintains the order of all non-zero elements.

It’s a textbook example of applying the two-pointer technique to solve array problems with optimal space and time efficiency.

Time and Space Complexity

MetricValue
Time ComplexityO(n)
Space ComplexityO(1) – in-place
  • The function scans the array twice at most—once for placing non-zeroes and once for appending zeroes.
  • No extra space is used, which is critical for performance-sensitive tasks.

Edge Cases to Consider

CaseOutputExplanation
[0, 0, 0][0, 0, 0]All elements are zero; nothing moves.
[1, 2, 3][1, 2, 3]No zero present; original order maintained.
[0, 1][1, 0]A simple case with one zero.
[4, 0, 5, 0, 6][4, 5, 6, 0, 0]Mixed zero and non-zero elements.

Real-World Relevance

This problem is more than just an academic exercise. Here’s how the pattern shows up in practice:

  • Data Cleaning: Removing or shifting invalid/missing values in data pipelines.
  • Gaming Engines: Managing player states or scores where inactive entities (represented by 0) are shifted.
  • Sparse Matrix Optimization: Moving non-zero values for efficient computation.
  • Real-time Systems: Reducing memory writes by modifying data structures in-place.

Conclusion

The Move Zeroes problem in Python is a fundamental coding challenge that prepares you for a wide variety of real-world and interview scenarios. It helps you master in-place operations, optimal pointer movement, and efficient list processing.

By solving this, you strengthen your command over array manipulation and gain insights into writing memory-conscious, performance-optimized code. Whether you’re preparing for technical interviews or building high-performance apps, this problem—and its solution—should be part of your core toolkit.

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Stay tuned on Vanita.ai for more deep dives into LeetCode 75 problems and real-world Python problem-solving tips.

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